![]() ![]() Is legal in C++11, because of parameterised constructor initialisation support, this: The important feature of this problem is that is CUDA uses a C++ compilation model, and Any field not provided during initialization is initialized to 1. , it is not needed to explicitly initialize the fields of ![]() In the case of your interest, you will have _host_ _device_ dim3(unsigned int vx = 1, unsigned int vy = 1, unsigned int vz = 1) : x(vx), y(vy), z(vz) ĭim3 grid(256) // defines a grid of 256 x 1 x 1 blocksĭim3 block(512,512) // defines a block of 512 x 512 x 1 threads Is an integer struct type defined in the file I would be clear where the configuration of the threads has been defined, and the 1D, 2D and 3D access pattern depends on how you are interpreting your data and also how you are accessing them by 1D, 2D and 3D blocks of threads. To sumup, it does it matter if you use a dim3 structure. Int y = blockIdx.y * blockDim.y + threadIdx.y Int x = blockIdx.x * blockDim.x + threadIdx.x You will always have access to threadIdx.y and threadIdx.z.Īs the thread ids start at zero, you can calculate a memory position as a row major order using also the The same happens for the blocks and the grid. ![]() When defining a variable of type dim3, any component left unspecified is initialized to 1. Is an integer vector type based on uint3 that is used to specify dimensions. However, the access pattern depends on how you are interpreting your data and also how you are accessing them by 1D, 2D and 3D blocks of threads. The memory is always a 1D continuous space of bytes. The way you arrange the data in memory is independently on how you would configure the threads of your kernel. ![]()
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